### Discussion :: Area - General Questions (Q.No.8)

P.Bharathi said: (Oct 2, 2010) | |

Saving on 2x metres = (0.59x) m. How this step arise ? Please explain me clearly. |

Sneha G.B said: (Jan 4, 2011) | |

saving 2x meters means...... 2x-1.41x=0.59x |

Ashu said: (Jan 15, 2011) | |

Use pyth. Theorem so you get the value of diagonal ac that is root 2 or 1. 41x. Now the distance saved by walking diagonally is 2x-1.41x i.e. 0.59x. |

Sandeep said: (Jan 27, 2011) | |

Any other way to solve this problem ? |

Kaps said: (Jun 11, 2011) | |

Easiest way told by ashu. |

J.Gopikrishna said: (Jun 15, 2011) | |

Please tell easy way to solve the problem? |

Suresh said: (Jun 17, 2011) | |

How Ac=root of2X? |

Sumit said: (Jun 30, 2011) | |

1.41*1.41x=2x |

Kb3 said: (Jul 17, 2011) | |

Let abcd be the square with each side of the square = 8m then ab+bc=2 x 8= 16m ac= sqrt(16)=4m solving = 16-4= 12m Hence, 4/12*100=33.33 approx. |

Abhi said: (Nov 28, 2011) | |

IN a sqare let us assume the sides be 3, 4 units then the diagonal will be 5 by pythagorus theorem ..thus 2 units are saved (7-5) .. total saved %=2/7*100 =28.57 i e 30% |

King Cobra said: (Dec 14, 2011) | |

Hey KB3. You are wrong. Solve by PYTHOGORUS theorem,, From the fig shown above. Root of AB square + BC square = AC. |

Scott said: (Jul 13, 2012) | |

From the fig shown above. Root of AB square + BC square = AC. |

Ajay said: (Jul 26, 2012) | |

Lets say sides of square is 10 and let diagonal be x therefore by Pythagoras theorem. X2 = (10) 2 + (10) 2 = 200. X = 10root2 = 10 x 14.1 (root2 = 1.412). Therefore 20 - 14.1 = 5.9. 5.9/20 = 0.30 i.e. approx 30%. |

Arpit Jain said: (Sep 1, 2012) | |

Hey kb3 u have used wrong formula its (square root of 2)*(X) ab+bc = 16m sqrt(2)*8 = 11.313 16-11.313 = 4.68 (4.68*100)/16 = 29.28% |

Sudhakar said: (Jul 12, 2013) | |

Suppose ab = 2, ac = 2 then ab+ac=4. Diagonal bc = ? Pythagoras Proof bc^2 = ac^2+ab^2 (here ^2 means square). bc^2= 4+4. bc=(square root of 8). bc= 2.83. Gain = 4-2.83 = 1.17. Gain(%) = (1.17/4)*100 = 29.28%. |

Atul Jain said: (Oct 28, 2013) | |

Let we have a square. starting from left top to right A,B,C,D. After that make a diagonal AC. As we know that we don't know the side of square then we assume x. Now we start to run from A to C then path is AB+BC and its value, is x+x = 2x. Then equation is AB+BC = 2x. Now the diagonal of the square formula is, d = square root of 2 x. d = 1.41x. Saving per cent is ((2x-1.41x)/2x)*100 . 29.5. approx 30. |

Suraj said: (Mar 23, 2014) | |

How the each side of square is 1m? |

Lakshya said: (Sep 20, 2014) | |

Why should we have to multiply 0.59x/2x by 100? somebody please help me. |

Anu said: (Sep 23, 2014) | |

What is that 1.41? |

Pragnya said: (Jan 9, 2015) | |

Please can anyone explain the last step in the solution? Which formula has been used there? |

Maaz said: (Jan 22, 2015) | |

Simple go for the formulas of Area of Square. There are two formulas: 1) Area of Square = (Sides)2. 2) Area of Square = 1/2 (Diagonals)2. Let 'S' is a side of square we know that all the sides of a square is equal. By first Formula Area will be S^2. Now putting this S^2 in 2nd Formula. We got the diagonal. By second formula: S^2 = 1/2(Diagonal)^2. Taking square root on both sides. Square root of 2*S = Diagonal. Now we have to find Diagonal. Diagonal = 1.414S(Square root of 2 = 1.414). So The difference between Diagonal and Edges is: 2S-1.414S = 0.59S. Percentage saved not by walk on edges = Extra Walk/Total Walk*100. = 0.59S/2S*100 = 30%. |

Anjali said: (Mar 6, 2015) | |

How it came (.59x)m? |

Namrata said: (Jun 10, 2015) | |

AC = root (2x). Root of 2 = 1.41. But where did the root of x disappeared? |

Namrata said: (Jun 10, 2015) | |

I will go with @Ajay's method where he took side as 10 instead of variable. Because is you take variable you go land up in confusion. AC = Root of (2x). Root of 2 = 1.41. But what about root of x? |

Amit Kumar Swain said: (Jun 29, 2015) | |

According to Pythagoras the side are 3&4 or diagonal 5. Edges are 7 then 7-5=2 (Different). (2/7)=(x/100). Solve x=28.57142857 (i.e approximately 30). |

Ak Nirala said: (Aug 1, 2015) | |

You (Amit) choose the sides of a rectangle not SQUARE. EXAMPLE METHOD. According to Pythagoras FOR SQUARE the sides are 2 & 2 or diagonal 2*sqrt(2) = 2*1.141 = 2.828 {where sqrt(2) = 1.141}. Edges are 2+2 then 4-2.828 = 1.172 (Difference). (1.172/4)*100 = 29.3 = 30 approx. Simple method: Edge of square let be x. Then diagonal of square will be 2 sqrt(x). Edge distance - Diagonal distance (difference). 2x-2sqrt(x) = x (2-sqrt(2)) = (2-1.414)x = 0.586x. %AGE. (0.586x/2x)*100 = (0.586/2)*100 = 29.3 (30 approx). |

Suresha E S said: (Sep 22, 2015) | |

AC = root (2x). Root of 2 = 1.41. But where did the root of x disappeared? |

Faziha said: (Oct 2, 2016) | |

We have to find saving distance from A to C. First, from edges the distance we have to calculate. So let's take side of a square as X So for A to C. We have to cross A to B then B to C. So, X + X = 2X. If we travel diagonally means the distance took is root of 2 multiplied by X. So, saving will b 2X - root 2 X. So (2.00 - 1.41) X = 0.59 X. Saving % is 0.59X/2X * 100 = 30%. |

Navaneeth said: (Feb 12, 2017) | |

If that person walked along edges. Approximately, what was the percent wasted by walking along the edges? Please give me the answer. |

Senthil said: (May 19, 2017) | |

@Amit kumar. How the edges are 7? |

Ramakanth said: (Jul 24, 2017) | |

Please tell me an easy way to solve the problem with the clear explanation. |

Rahul said: (Aug 17, 2017) | |

let us assume the side of square is 10 cm. In a square all sides are equal. To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)). In this case= Square root of (2*(10^2)) = 14.142. Distance Traveled=14.142. Distance if used the edge of the square= 10*2= 20. Saving=20-14.142=5.858. Saving in %=5.858/20 =30%. |

Prajakta said: (Oct 3, 2018) | |

Savings on 2xmeters = (0.59x)meter how? |

Riya said: (Feb 7, 2019) | |

@All. Along the edges, that means more than one side, so how come it has been decided that it is only 2 sides? Solution has been given only for 2 sides. Why? Why it can't be 4 sides? |

Saipriya said: (Apr 24, 2020) | |

Why do we take the percentage over 2x rather than 1.41x? |

Punni said: (May 30, 2020) | |

@Riya. Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C. We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt. |

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